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类型(2020新)北师大版四年级数学下册《25-解方程(一)》课件.ppt

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    2020新 25-解方程一 2020 北师大 四年级 数学 下册 25 方程 课件 下载 _四年级下册_北师大版(2024)_数学_小学
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    1、【2020新】北师大版四年级数学下册25-解方程(一)课件课后课后作业作业探索探索新知新知1课堂探究点课堂探究点2课时流程课时流程课堂课堂小结小结当堂当堂检测检测2g5g10g5g2g5552522g10g2g121212212210g gxx105g5gx5105x 515x 55155探究点探究点1 等式的性质(一)等式的性质(一)观察下图,你发现了什么规律?观察下图,你发现了什么规律?等式两边都加上(或减去)同一个数,等式仍然成立。等式两边都加上(或减去)同一个数,等式仍然成立。你能运用发现的规律解出我们前面列出的方程吗?你能运用发现的规律解出我们前面列出的方程吗?x210解:解:x22

    2、102 x8探究点探究点2 运用等式的性质(一)解方程运用等式的性质(一)解方程解方程。解方程。y712解:解:y7712723x45y19解:解:23x234523 x2219712,y19对了。对了。232245,x22对了。对了。小试牛刀小试牛刀(源于(源于典中点典中点)1看图填一填。看图填一填。(1)()个梨和个梨和()个菠萝一样重。两边同时各放个菠萝一样重。两边同时各放上上1个梨,天平个梨,天平()。(2)两边同时拿掉两边同时拿掉()个柿子,天平还平衡。个柿子,天平还平衡。1个个梨和梨和()个柿子同样重。个柿子同样重。31仍然平衡仍然平衡122填空。填空。(1)因为因为204060,

    3、所以,所以20402060()(2)因为因为602040,所以,所以60202040()(3)因为因为x2.410,所以,所以x2.42.410()(4)等式两边都加上等式两边都加上(或减去或减去)(),等式仍然,等式仍然成立。成立。20202.4同一个数同一个数3利用等式的性质解方程,填一填。利用等式的性质解方程,填一填。15160.6 0.634解方程。解方程。4.5x17.259x3.6(检验检验)x12.75x5.4(检验略检验略)归纳总结:归纳总结:(讲解源于(讲解源于典中点典中点)等式两边都加上等式两边都加上(或减去或减去)同一个数,同一个数,等式仍然成立,这就是等式的性质等式仍然

    4、成立,这就是等式的性质(一一)。小试牛刀小试牛刀(教材(教材P69练一练)练一练)1.请你画图或举例说说下面这句话的意思:请你画图或举例说说下面这句话的意思:等式两边都加上(或减去)同一个数,等式仍然成立。等式两边都加上(或减去)同一个数,等式仍然成立。略略2.看图列方程,并解方程。看图列方程,并解方程。y20502010 解:解:y2020 50201020 y 603.解方程。解方程。x192 x12.33.8解:解:x1919 219 x 21 解:解:x12.312.3 3.812.3 x 16.14.看图列方程,并解方程。看图列方程,并解方程。x419 解:解:x44 194 x 1

    5、5 x62486 解:解:x6262 48662 x 548 y5060180 解:解:y506050601805060 y705.看图回答问题。看图回答问题。(1)图中哪一段长度是()图中哪一段长度是(200 x)米?)米?(2)图中哪一段长度是()图中哪一段长度是(200y)米?)米?(3)根据上图,你能列出两个不同的方程吗?)根据上图,你能列出两个不同的方程吗?150米长的线段。米长的线段。500米长的线段。米长的线段。(答案不唯一答案不唯一)200 x150200y5006.在家或学校栽种一盘蒜苗,每在家或学校栽种一盘蒜苗,每2天测量一次蒜苗的高度,天测量一次蒜苗的高度,并做好数据记录

    6、。并做好数据记录。略略易错辨析易错辨析5下面的解法对吗?若不对,请改正。下面的解法对吗?若不对,请改正。x10.530 解:解:x10.510.5 3010.5 x 19.5 ()改正:改正:x10.530 解:解:x10.510.53010.5 x40.5辨析:没有掌握等式的性质辨析:没有掌握等式的性质(一一)。版权申明本文部分内容,包括文字、图片、以及设计等在网上搜集整理.版权为个人所有This article includes some parts,including text,pictures,and design.Copyright is personal ownership.用户可

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