基因组组装技术课件.pptx
- 【下载声明】
1. 本站全部试题类文档,若标题没写含答案,则无答案;标题注明含答案的文档,主观题也可能无答案。请谨慎下单,一旦售出,不予退换。
2. 本站全部PPT文档均不含视频和音频,PPT中出现的音频或视频标识(或文字)仅表示流程,实际无音频或视频文件。请谨慎下单,一旦售出,不予退换。
3. 本页资料《基因组组装技术课件.pptx》由用户(晟晟文业)主动上传,其收益全归该用户。163文库仅提供信息存储空间,仅对该用户上传内容的表现方式做保护处理,对上传内容本身不做任何修改或编辑。 若此文所含内容侵犯了您的版权或隐私,请立即通知163文库(点击联系客服),我们立即给予删除!
4. 请根据预览情况,自愿下载本文。本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
5. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007及以上版本和PDF阅读器,压缩文件请下载最新的WinRAR软件解压。
- 配套讲稿:
如PPT文件的首页显示word图标,表示该PPT已包含配套word讲稿。双击word图标可打开word文档。
- 特殊限制:
部分文档作品中含有的国旗、国徽等图片,仅作为作品整体效果示例展示,禁止商用。设计者仅对作品中独创性部分享有著作权。
- 关 键 词:
- 基因组 组装 技术 课件
- 资源描述:
-
1、基因组组装 2019.10.29一、Genome survey Kmer:a continuous nucleic acid sequences,the length is K bp.Suppose the genome is unique to K,we can get G different kmers.when generate a read,the possibility of a certain kmer be sequenced is(L-K+1)/G.L/G is very small,the n_r is very large,this is obey to Poisson d
2、istribution.So,d_k=(L-K+1)/G*n_r n_k=(L-K+1)*n_rthen,G=n_k/d_kQuality control and filtering Reads having a N over 10%of its length.Reads from short insert-size libraries having more than 65%bases with the quality 7,and the reads from large insert-size libraries that contained more than 80%bases with
3、 the quality 7.Read 1 and read 2 of two paired-end reads that were completely identical(and thus considered to be the products of PCR duplication).Error correction before assembly二、SOAPdenovo algorithm SOAPdenovo was developed to assemble large genomes,such as human,it also works well for small geno
4、mes like bacteria.Include five major steps:De bruijn graph construction Graph simplification and obtain contigs Pair-end reads mapping to contigs Construct scaffolds Gap filling with pair-end readsSequence assembly refers to aligning and merging fragments to a much longer DNA sequence in order to re
展开阅读全文