供应链管理全册配套精品完整课件.ppt
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1、 3 供应链管理导论 物流网络构造 库存管理与风险分担 信息价值 供应链整合 战略联盟 采购及外包战略 供应链管理的全球化问题 协调的产品与供应链设计 顾客价值和供应链管理 供应链管理的信息技术 供应链管理决策支持系统 4 马士华等.供应链管理.高等教育出版社,2010 大卫辛奇利维等著,季建华等译.供应链设计与管理 :概念、战略与案例研究.中国财政经济出版社,2010 David Simchi-Levi, et al. Designing 1 Product Considering transportation costs only Customer data Original Data h
2、ad 18000 ship-to locations Aggregated Data had 800 ship-to locations Total demand was the same in both cases 83 Total Cost:$5,796,000 Total Customers: 18,000 Total Cost:$5,793,000 Total Customers: 800 Cost Difference 0.05% 84 实际中通常使用以下方法汇总数据: 将需求点汇总为150200个区域 -若依顾客服务水平或配送频率分类,则每一类将有150200个汇总点 确保每个区域
3、的总需求量大致相等(每个区域的地理面积可能 并不相等) 在区域的中心放置汇总点 将产品汇总成2050个产品组 85 Companies may have hundreds to thousands of individual items in their production line Variations in product models or style Same products are packaged in many sizes Collecting all data and analyzing them is impractical for so many product gro
4、ups 86 Place all SKUs (Stock-Keeping Units,最小存货单位) into a source-group A source group is a group of SKUs all sourced from the same place(s) Within each of the source-groups, aggregate the SKUs by similar logistics characteristics Weight Volume Holding Cost 87 0.0 10.0 20.0 30.0 40.0 50.0 60.0 70.0 0
5、.0000.0100.0200.0300.0400.0500.0600.0700.0800.0900.100 Volume (pallets per case) Weight (lbs per case) Rectangles illustrate how to cluster SKUs. 88 5 Plants 25 Potential Warehouse Locations Distance-based Service Constraints Inventory Holding Costs Fixed Warehouse Costs Product Aggregation 46 Origi
6、nal products 4 Aggregated products were created 89 Total Cost:$104,564,000 Total Products: 46 Total Cost:$104,599,000 Total Products: 4 Cost Difference : 0.03% 90 运输费率估计是构建有效配送网络设计模型的重要环节 大多数运输费率(包括卡车、铁路及其他运输方式)与 运输距离呈线性关系,而不与运量呈线性关系 运输费率估计 公司内部车队,涉及每辆卡车的年费用、年行驶里程、年运 量、有效运力 公司外部车队,分为整车运输和零担运输 91 整车运
7、输(TL: Truck Load) TL 承运人为顾客提供区域间的运输费率表,费率表中列有 任意两区域间每辆卡车每英里的运输费用 零担运输(LTL: Less Than Truck Load) LTL 运输费率有三种:等级(Class)费率、特价( Exception)费率、特定商品(Commodity)费率 92 等级(Class) 是标准费率,几乎所有的产品或商品都有相应的标准费率。它们可根据 分类费率表(Classification Tariff)被分类,每种商品都有一个类别 (Rating or Class) -如火车运输采用 Uniform Freight Classificatio
8、n,含31种等级(从400到 13) -而卡车运输采用 National Motor Freight Classification,含23种货物等 级(从500到35) 等级越高,其运输费率就越高 A number of factors are involved in determining a products specific class. These include -Density -Ease or difficulty of handling and transporting -Liability for damage 93 特价(Exception)费率 用来提供较低费率 特定商品
9、(Commodity)费率 提供特定商品的运输费率 LTL 计费工具:基于邮政编码的LTL费率计算系统CZAR-Lite 为货主提供一个公平的计价系统,并防止任何承运人偏离市 场的行为而影响货主的选择 94 95 运输成本是运输距离的一个函数,因此我们需要一个工 具来估计距离 69:美国地区一个纬度的大约英里数 绕行系数(Circuity Factor):都市区=1.3;美国大陆 =1.14(乘上Dab,以考虑实际的道路距离) 地理信息系统(GIS)的应用 2 2 69 babaab latlatlonlonD 22 1 2 sincoscos 2 sinsin692 ba ba ba ab
10、lonlon latlat latlat D 96 搬运成本(Handling Costs) 包括劳工及公用设施成本 与仓库年物流量成比例 固定成本(Fixed Costs) 包括所有不与仓库年物流量成比例的成本 通常固定成本与仓库大小(容量)成比例,但不是线性的 持有成本(Carrying Costs) 代表库存持有成本,与平均库存水平成比例 97 有了仓库年货物流量后,该如何估计实际需要的空 间(1000单位) 仓库年货物流量除以库存周转率可得平均库存水平 (周转率=10;AI=100) 需要的储存空间约为平均库存的两倍 将所需的储存空间乘上一大于1的系数,通常为3 即:估计容量 = 单位
11、储存空间 X 平均库存水平 X 2 X 3 98 好的位置必须满足下列条件: 地理及基础设施条件 自然资源及劳力的可得性 当地产业及税收制度 公共利益 99 定义服务水平有许多方法,例如我们可在每个顾客与提 供其服务的仓库间限定一个最大距离,这可以保证仓库 能在一合理的时间内服务顾客 但是我们较难提供给那些位于偏远地区的顾客与其它顾 客相同水平的服务。因此,常定义服务水平为某一比例 的顾客距离提供其服务的仓库不可超过某一距离 例如要求95%顾客所在的位置距离提供其服务的仓库不可超过 200英里 100 战略层次的决策(包括设计分销网络)对公司而言有长 期的影响,特别是与仓库的数量、位置、大小有
12、关的决 策,对公司的影响将长达3-5年,也就是说设计网络时要 考虑未来几年顾客需求的变化 通常会用基于情景(Scenario-Based)的方法来解决 $- $10 $20 $30 $40 $50 $60 $70 $80 $90 0246810 Number of Warehouses Cost (millions $) Total Cost Transportation Cost Fixed Cost Inventory Cost Avg. # of WH31425 Pharmaceuticals Food CompaniesChemicals - High margin product -
13、 Service not important (or easy to ship express) - Inventory expensive relative to transportation - Low margin product - Service very important - Outbound transportation expensive relative to inbound 103 确保数据及模型正确地反映网络设计问题的程序,称为 模型及数据的验证(Model and Data Validation) 通常利用模型和搜集的数据重构现有的网络结构,并将 模型的输出结果与现有
14、的数据作比较 104 这些数据与公司的会计信息相比较,通常是找出数据、有问题的 假设、建模缺陷等方面错误的最佳方法。例如在某一个案中,经 验证程序计算出来的运输成本与会计数据建议的成本相比较,一 直被低估 经仔细检查后,咨询人员下结论说是卡车的有效承载量只有可载重量的30% ,也就是说卡车以很少的承载量运送 对网络结构做局部或小的改变,看系统如何评估对成本及服务水 平的影响(灵敏度分析)。此步骤包括提出一些假设性的问题, 例如: 如果关闭系统中某一现有的仓库有什么影响 或者变换现存网络中的物料流程,成本会有何改变 105 使物流网络架构最优化的技术 数学上的最优化方法(Mathematical
15、 Optimization Techniques) -精确算法(Exact Algorithms):一定能找出最佳解 -启发式算法(Heuristics):能找出好的解,但未必是最优解 仿真模型(Simulation Models) -Provide a mechanism to evaluate specified design alternatives created by the designer 106 Single product Two plants p1 and p2 Plant p1 has an unlimited capacity Plant p2 has an annua
16、l capacity of 60,000 units The two plants have the same production costs There are two warehouses w1 and w2 with identical warehouse handling costs There are three markets areas c1,c2 and c3 with demands of 50,000, 100,000 and 50,000, respectively 107 WarehouseP1P2C1C2C3 W104345 W252212 Table: Distr
17、ibution Costs per Unit 108 D = 50,000 D = 100,000 D = 50,000 Cap = 60,000 $4 $5 $2 $3 $4 $5 $2 $1 $2 $0 Production costs are the same, warehousing costs are the same 109 D = 50,000 D = 100,000 D = 50,000 Cap = 60,000 $5 x 140,000 $2 x 60,000 $2 x 50,000 $1 x 100,000 $2 x 50,000 Total Costs = $1,120,
18、000 Assign each market to closet warehouse. Then assign each plant based on cost. 110 Assign each market based on total delivery cost D = 50,000 D = 100,000 D = 50,000 Cap = 60,000 $4 $5 $2 $3 $4 $5 $2 $1 $2 $0 P1 to WH1$3 P1 to WH2$7 P2 to WH1$7 P2 to WH 2$4 P1 to WH1$4 P1 to WH2$6 P2 to WH1$8 P2 t
19、o WH 2$3 P1 to WH1$5 P1 to WH2$7 P2 to WH1$9 P2 to WH 2$4 Market #1 is served by WH1, Markets 2 and 3 are served by WH2 111 D = 50,000 D = 100,000 D = 50,000 Cap = 60,000 $5 x 90,000 $2 x 60,000 $3 x 50,000 $1 x 100,000 $2 x 50,000 $0 x 50,000 P1 to WH1$3 P1 to WH2$7 P2 to WH1$7 P2 to WH 2$4 P1 to W
20、H1$4 P1 to WH2$6 P2 to WH1$8 P2 to WH 2$3 P1 to WH1$5 P1 to WH2$7 P2 to WH1$9 P2 to WH 2$4 Total Cost = $920,000 112 The problem described earlier can be framed as the following linear programming problem Let x(p1,w1), x(p1,w2), x(p2,w1) and x(p2,w2) be the flows from the plants to the warehouses x(
21、w1,c1), x(w1,c2), x(w1,c3) be the flows from the warehouse w1 to customer zones c1, c2 and c3 x(w2,c1), x(w2,c2), x(w2,c3) be the flows from warehouse w2 to customer zones c1, c2 and c3 113 The problem we want to solve is: min 0 x(p1,w1) + 5x(p1,w2) + 4x(p2,w1) + 2x(p2,w2) + 3x(w1,c1) + 4x(w1,c2) +
22、5x(w1,c3) + 2x(w2,c1) + 2x(w2,c3) Subject to the following constraints: x(p2,w1) + x(p2,w2) 99% for many products with high profit margin, high volume and low variability. Service level Low customer promise times Classic PUSH STRATEGY High shortages Huge risk PULL STRATEGY not feasible because of lo
23、ng lead times 201 OBJECTIVES: Reduce inventory and financial risks Provide customers with competitive response times. ACHIEVE THE FOLLOWING: Determining the optimal location of inventory across the various stages Calculating the optimal quantity of safety stock for each component at each stage Hybri
24、d strategy of Push and Pull Push Stages produce to stock where the company keeps safety stock Pull stages keep no stock at all. Challenge: Identify the location where the strategy switched from Push-based to Pull-based Identify the Push-Pull boundary Benefits: For same lead times, safety stock reduc
25、ed by 40 to 60% Company could cut lead times to customers by 50% and still reduce safety stocks by 30% 202 FIGURE 3-11: How to read the diagrams 203 If Montgomery facility reduces committed lead time to 13 days assembly facility does not need any inventory of finished goods Any customer order will t
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